Math Problem Statement

3y − 1 = 5

Solution

To solve the equation 3y1=53y - 1 = 5, follow these steps:

  1. Add 1 to both sides of the equation to isolate the term with yy: 3y1+1=5+13y - 1 + 1 = 5 + 1 Simplifying this: 3y=63y = 6

  2. Divide both sides by 3 to solve for yy: y=63y = \frac{6}{3} y=2y = 2

The solution is y=2y = 2.

Would you like more details or have any questions?

Here are some related questions to consider:

  1. What happens if you subtract 1 from both sides instead of adding?
  2. How do you check if your solution for yy is correct?
  3. Can you solve a similar equation like 4y3=94y - 3 = 9?
  4. What if the equation had fractions, like 3y21=5\frac{3y}{2} - 1 = 5?
  5. How would you graph this equation on a coordinate plane?

Tip: Always check your solution by substituting it back into the original equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Basic linear equation form: ax + b = c

Theorems

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Suitable Grade Level

Grades 6-8