To solve for \( x \) in the equation:

\[
-3x + 2c = 3
\]

### Steps:

1. **Isolate the term with \( x \):**

   Subtract \( 2c \) from both sides:
   \[
   -3x = 3 - 2c
   \]

2. **Solve for \( x \):**

   Divide both sides by \( -3 \) to get \( x \) alone:
   \[
   x = \frac{3 - 2c}{-3}
   \]

3. **Simplify the equation:**

   Distribute the negative sign in the denominator:
   \[
   x = \frac{-3 + 2c}{3} \quad \text{or} \quad x = \frac{2c - 3}{3}
   \]

So, the solution for \( x \) is:

\[
x = \frac{2c - 3}{3}
\]

Would you like more details on any of the steps?

### Related Questions:
1. What if the equation was \( -3x + 2c = 0 \)?
2. How do you solve for \( c \) instead of \( x \)?
3. How would the solution change if the coefficient of \( x \) was positive?
4. What if the equation was \( -3x + 2c = 3 + x \)?
5. How do you graph the equation \( -3x + 2c = 3 \)?

### Tip:
When solving linear equations, always isolate the variable you're solving for by performing inverse operations.

Learn how to solve the linear equation -3x + 2c = 3 for x with a detailed step-by-step solution. This problem covers key algebraic concepts such as isolating variables and inverse operations. Suitable for students in Grades 6-8.

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