The problem involves solving the equation $3x + 2 = y$ when $y = -1$. Let's solve for $x$.

Steps:

1. Substitute $y = -1$ into the equation $3x + 2 = y$: $3x + 2 = -1$

2. Subtract 2 from both sides: $3x = -1 - 2$ $3x = -3$

3. Divide both sides by 3: $x = \frac{-3}{3}$ $x = -1$

Final Answer:

$x = -1$

Would you like a detailed explanation of this process or assistance with another part of the graph? Here are some related questions to explore:

1. How can you confirm that a point lies on the line $y = 3x + 2$?
2. How do you graph a linear equation like $y = 3x + 2$?
3. What is the slope of the line represented by $y = 3x + 2$?
4. How would you find the $y$-intercept of the equation $y = 3x + 2$?
5. What happens if $y = 0$ instead of $y = -1$? How does that change $x$?

Tip: Always check your solution by substituting back into the original equation to verify correctness!