To solve the equation \(2y + 6 = 8y - 102\), we'll start by isolating \(y\) on one side.

### Step-by-step Solution:

1. **Subtract \(2y\) from both sides:**

\[
2y + 6 - 2y = 8y - 102 - 2y
\]

\[
6 = 6y - 102
\]

2. **Add 102 to both sides:**

\[
6 + 102 = 6y - 102 + 102
\]

\[
108 = 6y
\]

3. **Divide by 6 to solve for \(y\):**

\[
y = \frac{108}{6}
\]

\[
y = 18
\]

### Solution:
The value of \(y\) is \(18\).

Would you like more details or have any questions?

### Related Questions:

1. How do you solve a similar equation with different coefficients?
2. What is the process for checking if your solution to a linear equation is correct?
3. How do you solve linear equations with fractions?
4. Can you explain how to solve equations involving absolute values?
5. What happens if an equation has no solution or infinitely many solutions?

#### Tip:
Always double-check your solution by substituting it back into the original equation!

Discover how to solve the linear equation 2y + 6 = 8y - 102 with a step-by-step explanation. This problem focuses on basic algebraic concepts and the properties of equality, perfect for students in Grades 6-8.

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