The given equation is:

$2x - 4y = 8$

This is a linear equation in two variables, $x$ and $y$. Let's solve it for both $x$ and $y$.

Solving for $y$:

1. Start with the equation: $2x - 4y = 8$

2. Isolate $y$: $-4y = 8 - 2x$

3. Divide both sides by -4: $y = \frac{2x - 8}{4}$

4. Simplify: $y = \frac{x}{2} - 2$

So, the equation in slope-intercept form is: $y = \frac{1}{2}x - 2$

This shows that the slope of the line is $\frac{1}{2}$ and the y-intercept is $-2$.

If you'd like further details or have any questions, feel free to ask!

Here are 5 related questions:

1. How would you find the x-intercept of the line $2x - 4y = 8$?
2. What is the graphical representation of the equation $y = \frac{1}{2}x - 2$?
3. How can you convert this equation into standard form $Ax + By = C$?
4. What happens to the graph of the line if the slope changes?
5. How would you find the perpendicular line to $y = \frac{1}{2}x - 2$?

Tip: When solving linear equations, converting them into slope-intercept form $y = mx + b$ makes it easier to understand the slope and intercept visually.