Math Problem Statement

2x+3=10

Solution

Let's solve the equation 2x+3=102x + 3 = 10.

Steps:

  1. Isolate the term with xx: Subtract 3 from both sides of the equation: 2x+33=1032x + 3 - 3 = 10 - 3 This simplifies to: 2x=72x = 7

  2. Solve for xx: Divide both sides of the equation by 2: 2x2=72\frac{2x}{2} = \frac{7}{2} This simplifies to: x=72x = \frac{7}{2}

Thus, the solution is: x=72orx=3.5x = \frac{7}{2} \quad \text{or} \quad x = 3.5

Would you like further details or have any other questions?

Here are 5 related questions:

  1. How do you solve equations with fractions?
  2. What happens if the equation has a negative number instead of 3?
  3. How do you handle equations where the variable is on both sides?
  4. Can you solve quadratic equations like this one?
  5. What is the process for solving an inequality?

Tip: Always perform the same operation to both sides of the equation to maintain the equality.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Algebra

Formulas

Ax + B = C
x = (C - B) / A

Theorems

Solving for a variable in a linear equation

Suitable Grade Level

Grades 7-8