To solve the equation \(2h + \frac{1}{3} = 7\), follow these steps:

1. **Isolate the term with \(h\)**:
   \[
   2h = 7 - \frac{1}{3}
   \]

2. **Subtract \(\frac{1}{3}\) from 7**:
   \[
   2h = \frac{21}{3} - \frac{1}{3} = \frac{20}{3}
   \]

3. **Solve for \(h\)** by dividing both sides by 2:
   \[
   h = \frac{\frac{20}{3}}{2} = \frac{20}{6} = \frac{10}{3}
   \]

So, \( h = \frac{10}{3} \) or approximately \( h \approx 3.33 \).

Would you like a detailed explanation of any steps? Here are some related questions:

1. How do you solve linear equations with fractions?
2. What are the steps to isolate a variable in an equation?
3. How do you add and subtract fractions?
4. What are some real-life applications of solving equations like this?
5. How do you simplify fractions?

**Tip:** When dealing with fractions in equations, it's often easier to eliminate them by multiplying every term by the denominator.

Learn how to solve the linear equation 2h + 1/3 = 7 with a detailed step-by-step solution. This problem covers linear equations involving fractions and how to isolate the variable h. Suitable for students in Grades 7-9.

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