Math Problem Statement

2(4+3x)=5(x-1)

Solution

Let's solve the equation step by step.

Given equation:

2(4+3x)=5(x1)2(4 + 3x) = 5(x - 1)

Step 1: Expand both sides.

Expand both sides of the equation by distributing the constants outside the parentheses.

2×4+2×3x=5×x5×12 \times 4 + 2 \times 3x = 5 \times x - 5 \times 1 This simplifies to: 8+6x=5x58 + 6x = 5x - 5

Step 2: Move the terms involving xx to one side.

Subtract 5x5x from both sides: 8+6x5x=58 + 6x - 5x = -5 Simplify: 8+x=58 + x = -5

Step 3: Isolate the variable xx.

Subtract 8 from both sides: x=58x = -5 - 8 x=13x = -13

Thus, the solution is: x=13x = -13

Would you like more details on any of these steps?

Here are 5 related questions you might consider:

  1. How do you handle equations with more complex parentheses?
  2. What happens if both sides of the equation have terms with variables?
  3. Can you explain why we distribute the constants?
  4. How would you solve this if there were fractions involved?
  5. How does this change if xx appears on one side only?

Tip: Always check your solution by plugging it back into the original equation!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Distributive Property

Formulas

a(b + c) = ab + ac
Linear equation solving

Theorems

Distributive Property
Properties of Equality

Suitable Grade Level

Grades 7-9