Let's solve the equation step by step.

### Given equation:
\[
2(4 + 3x) = 5(x - 1)
\]

### Step 1: Expand both sides.
Expand both sides of the equation by distributing the constants outside the parentheses.

\[
2 \times 4 + 2 \times 3x = 5 \times x - 5 \times 1
\]
This simplifies to:
\[
8 + 6x = 5x - 5
\]

### Step 2: Move the terms involving \(x\) to one side.
Subtract \(5x\) from both sides:
\[
8 + 6x - 5x = -5
\]
Simplify:
\[
8 + x = -5
\]

### Step 3: Isolate the variable \(x\).
Subtract 8 from both sides:
\[
x = -5 - 8
\]
\[
x = -13
\]

Thus, the solution is:
\[
x = -13
\]

Would you like more details on any of these steps?

Here are 5 related questions you might consider:
1. How do you handle equations with more complex parentheses?
2. What happens if both sides of the equation have terms with variables?
3. Can you explain why we distribute the constants?
4. How would you solve this if there were fractions involved?
5. How does this change if \(x\) appears on one side only?

**Tip**: Always check your solution by plugging it back into the original equation!

Discover how to solve the linear equation 2(4 + 3x) = 5(x - 1) with a clear step-by-step guide. This solution covers essential algebraic concepts such as the distributive property and isolating variables. Ideal for students in Grades 7-9.

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