To solve the equation \( 16x - 13 = 6x + 7 \), follow these steps:

1. **Isolate the variable terms on one side**: Subtract \( 6x \) from both sides to eliminate \( 6x \) on the right.
   \[
   16x - 6x - 13 = 6x - 6x + 7
   \]
   Simplifying this gives:
   \[
   10x - 13 = 7
   \]

2. **Isolate the constant term**: Add 13 to both sides to eliminate \(-13\) on the left.
   \[
   10x - 13 + 13 = 7 + 13
   \]
   Simplifying this gives:
   \[
   10x = 20
   \]

3. **Solve for \( x \)**: Divide both sides by 10.
   \[
   x = \frac{20}{10}
   \]
   Simplifying this gives:
   \[
   x = 2
   \]

So, the solution is \( x = 2 \).

Would you like more details or have any questions?

Here are some related questions you might find interesting:

1. What would happen if the equation had \(16x + 13 = 6x + 7\)?
2. How would you solve \(16x - 13 = 6x - 7\)?
3. How do you solve for \(x\) if the coefficients are negative, like \( -16x + 13 = -6x + 7\)?
4. What if the equation were \(16x - 13 = 6x + 2x + 5\)?
5. How would you solve an equation like \( 16x - 13 = 0 \)?

**Tip**: Always start by simplifying both sides of an equation as much as possible before solving for the variable.

Learn how to solve the linear equation 16x - 13 = 6x + 7 with a detailed step-by-step solution. This problem involves basic algebraic concepts, such as isolating variables and solving for x. Suitable for students in Grades 6-8.

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