Let's solve the equation:

\[
16 - 2t = t + 9 + 4t
\]

### Step 1: Combine like terms on both sides.
- On the left side, we have \(16 - 2t\).
- On the right side, combine \(t\) and \(4t\) to get \(5t\):

\[
16 - 2t = 9 + 5t
\]

### Step 2: Move the variable terms to one side.
Add \(2t\) to both sides to eliminate \(-2t\) on the left:

\[
16 = 9 + 7t
\]

### Step 3: Isolate the variable.
Subtract 9 from both sides:

\[
16 - 9 = 7t
\]

\[
7 = 7t
\]

### Step 4: Solve for \(t\).
Divide both sides by 7:

\[
t = 1
\]

### Solution:
The solution to the equation is \(t = 1\).

Do you want further details or have any questions?

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Here are 5 related questions to consider:
1. How would the solution change if the equation were \(16 - 3t = t + 9 + 4t\)?
2. Can you solve \(2x + 5 = 3x - 8\)?
3. What happens if you move all terms to one side before simplifying?
4. How do you handle equations with fractions, like \( \frac{2}{3}x + 4 = x - 2\)?
5. What is the process for solving quadratic equations?

**Tip:** When solving linear equations, always aim to simplify and combine like terms first for easier calculations.

Learn how to solve the linear equation 16 - 2t = t + 9 + 4t with a step-by-step solution. This problem focuses on key algebraic techniques, such as combining like terms and isolating the variable. Suitable for students in Grades 6-8.

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