We are given the equation:

\[
-11 - 3k = k + 5
\]

Let's solve for \( k \) step by step.

### Step 1: Move all terms involving \( k \) to one side
Add \( 3k \) to both sides:

\[
-11 = k + 3k + 5
\]

This simplifies to:

\[
-11 = 4k + 5
\]

### Step 2: Move the constant terms to the other side
Subtract 5 from both sides:

\[
-11 - 5 = 4k
\]

Simplifying:

\[
-16 = 4k
\]

### Step 3: Solve for \( k \)
Now, divide both sides by 4:

\[
k = \frac{-16}{4} = -4
\]

So, the solution is:

\[
k = -4
\]

Would you like more details or have any questions? 

Here are some related questions:
1. What happens if you change the constant term on the right side of the equation?
2. How would the solution change if the coefficient of \( k \) was different?
3. Can you solve for \( k \) if the equation was quadratic?
4. How does moving terms affect the balance of an equation?
5. What if the equation involved fractions or decimals?

**Tip:** Always

Learn how to solve the linear equation -11 - 3k = k + 5 step by step. This problem involves key algebraic concepts such as balancing equations and isolating variables, making it suitable for students in Grades 6-8.

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