Solve for bb.
10, b, plus, 18, equals, 28
10b+18=
28

Let's solve the equation for \( b \):

\[
10b + 18 = 28
\]

1. **Subtract 18 from both sides** to isolate the term with \( b \):

\[
10b + 18 - 18 = 28 - 18
\]

\[
10b = 10
\]

2. **Divide both sides by 10** to solve for \( b \):

\[
b = \frac{10}{10}
\]

\[
b = 1
\]

So, \( b = 1 \).

Would you like more details, or do you have any questions? Here are some related questions:

1. What happens if you multiply both sides of the equation by a number?
2. How would the solution change if the equation was \( 10b + 18 = 38 \)?
3. Can you explain the importance of balancing equations in algebra?
4. What is the next step if \( 10b + 18 \) was equal to a negative number?
5. How can you check if the solution \( b = 1 \) is correct?

**Tip:** Always double-check your work by substituting the solution back into the original equation.

Learn how to solve the linear equation 10b + 18 = 28 with a step-by-step explanation. This solution focuses on fundamental algebraic concepts, including balancing equations and properties of equality. Suitable for students in Grades 6-8.

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