To solve the equation \(10b + 18 = 28\), we will isolate the variable \(b\). Here are the steps:

1. **Subtract 18 from both sides** to remove the constant term from the left side:
   \[
   10b + 18 - 18 = 28 - 18
   \]
   \[
   10b = 10
   \]

2. **Divide both sides by 10** to solve for \(b\):
   \[
   \frac{10b}{10} = \frac{10}{10}
   \]
   \[
   b = 1
   \]

So, the solution is:
\[
\boxed{b = 1}
\]

Would you like a detailed explanation or have any questions? Here are some related questions you might find interesting:

1. How do you solve equations with variables on both sides?
2. What is the general strategy for solving linear equations?
3. Can you solve for \(b\) if the equation were \(10b + 18 = 30\)?
4. How do you solve equations involving fractions?
5. What happens if the coefficient of \(b\) is a fraction?

**Tip:** Always perform the same operation on both sides of an equation to keep it balanced!

Learn how to solve the equation 10b + 18 = 28 step-by-step with a detailed explanation. This problem covers basic algebraic concepts, including linear equations and solving for variables. Suitable for students in Grades 5-7.

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