Math Problem Statement

1/6+x=71

Solution

To solve the equation 16+x=71\frac{1}{6} + x = 71, follow these steps:

Step 1: Subtract 16\frac{1}{6} from both sides.

x=7116x = 71 - \frac{1}{6}

Step 2: Express 71 as a fraction with a denominator of 6.

71=426671 = \frac{426}{6} Now the equation is: x=426616x = \frac{426}{6} - \frac{1}{6}

Step 3: Subtract the fractions.

x=42616=4256x = \frac{426 - 1}{6} = \frac{425}{6}

Thus, the solution is: x=425670.83x = \frac{425}{6} \approx 70.83

Would you like further details or have any questions?

Here are some related questions to explore:

  1. How would you solve 14+x=100\frac{1}{4} + x = 100?
  2. What happens when 16+x=71\frac{1}{6} + x = -71?
  3. Can you solve 5x+1=715x + 1 = 71?
  4. What if the equation were 16x=71\frac{1}{6} - x = 71?
  5. How do you solve equations with fractions on both sides?

Tip: When subtracting fractions, always ensure they have the same denominator to make the process easier.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Fractions

Formulas

x = a - b (Solving for x)
Fraction Subtraction: a/b - c/b = (a - c)/b

Theorems

Properties of Equality
Rules for Subtracting Fractions

Suitable Grade Level

Grades 6-8