To solve the equation \( \frac{1}{6} + x = 71 \), follow these steps:

### Step 1: Subtract \( \frac{1}{6} \) from both sides.
\[
x = 71 - \frac{1}{6}
\]

### Step 2: Express 71 as a fraction with a denominator of 6.
\[
71 = \frac{426}{6}
\]
Now the equation is:
\[
x = \frac{426}{6} - \frac{1}{6}
\]

### Step 3: Subtract the fractions.
\[
x = \frac{426 - 1}{6} = \frac{425}{6}
\]

Thus, the solution is:
\[
x = \frac{425}{6} \approx 70.83
\]

Would you like further details or have any questions?

Here are some related questions to explore:

1. How would you solve \( \frac{1}{4} + x = 100 \)?
2. What happens when \( \frac{1}{6} + x = -71 \)?
3. Can you solve \( 5x + 1 = 71 \)?
4. What if the equation were \( \frac{1}{6} - x = 71 \)?
5. How do you solve equations with fractions on both sides?

**Tip:** When subtracting fractions, always ensure they have the same denominator to make the process easier.

Learn how to solve the linear equation 1/6 + x = 71 with step-by-step instructions. This solution covers essential algebraic concepts like solving for variables and subtracting fractions. Suitable for students in Grades 6-8.

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