Let's solve the equation:

\[
\frac{1}{3}(21y + 39) = -36
\]

### Step 1: Distribute the \(\frac{1}{3}\) to the terms inside the parentheses:

\[
\frac{1}{3} \times 21y + \frac{1}{3} \times 39 = -36
\]

This simplifies to:

\[
7y + 13 = -36
\]

### Step 2: Subtract 13 from both sides to isolate the term with \(y\):

\[
7y = -36 - 13
\]

Simplify the right side:

\[
7y = -49
\]

### Step 3: Divide both sides by 7 to solve for \(y\):

\[
y = \frac{-49}{7}
\]

Simplify:

\[
y = -7
\]

Thus, the solution is \(y = -7\).

Would you like further details or clarification on any step?

Here are 5 related questions:
1. How do you solve equations involving fractions?
2. What is the distributive property and how is it used?
3. How do you check if your solution to an equation is correct?
4. How do you isolate variables in an equation?
5. How does dividing by negative numbers affect equations?

**Tip:** Always simplify both sides of an equation before solving to make the process easier.

This page provides a step-by-step solution to the linear equation 1/3(21y + 39) = -36, demonstrating how to apply the distributive property and isolate the variable y. A helpful resource for students in Grades 7-9 learning basic algebra and equation-solving techniques.

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