Math Problem Statement

Solve the inequality: (5x - (3x - 2) - 2.5(2 - x/3) + 5x)/20 ≤ (2x - 1/5 - 3(5x - 2) - 3x)/15

Solution

The image you uploaded contains a complex inequality expression involving fractions and variables. I will transcribe and solve the inequality step by step.

The inequality is as follows:

5x(3x2)2.5(2x3)+5x202x153(5x2)3x15\frac{5x - (3x - 2) - 2.5 \left( 2 - \frac{x}{3} \right) + 5x}{20} \leq \frac{2x - \frac{1}{5} - 3(5x - 2) - 3x}{15}

Step-by-Step Solution

  1. Simplify each side separately:
  • On the left side: 5x(3x2)=5x3x+2=2x+25x - (3x - 2) = 5x - 3x + 2 = 2x + 2 Also, simplify the term with the fraction: 2.5(2x3)=2.5(2)+2.5(x3)=5+2.5x3-2.5 \left( 2 - \frac{x}{3} \right) = -2.5(2) + 2.5\left( \frac{x}{3} \right) = -5 + \frac{2.5x}{3} Putting this all together, the left side becomes: 2x+25+2.5x3+5x20=7x3+2.5x320\frac{2x + 2 - 5 + \frac{2.5x}{3} + 5x}{20} = \frac{7x - 3 + \frac{2.5x}{3}}{20}

  • On the right side: Simplify each term: 3(5x2)=15x63(5x - 2) = 15x - 6 The right side becomes: 2x1515x+63x15=16x+61515\frac{2x - \frac{1}{5} - 15x + 6 - 3x}{15} = \frac{-16x + 6 - \frac{1}{5}}{15}

  1. Clear the denominators by multiplying both sides by the least common denominator (LCM of 20 and 15, which is 60):

Multiplying each side by 60 to eliminate the fractions.

Let me proceed with this simplification.After multiplying both sides by 60, we get the following simplified inequality:

23.5x923.264x23.5x - 9 \leq 23.2 - 64x

Step-by-Step Solution from Here:

  1. Move all terms involving xx to one side and constants to the other side: 23.5x+64x23.2+923.5x + 64x \leq 23.2 + 9 87.5x32.287.5x \leq 32.2

  2. Solve for xx: x32.287.5x \leq \frac{32.2}{87.5} x0.368x \leq 0.368

Thus, the solution to the inequality is: x0.368x \leq 0.368

Would you like more details or clarification on any steps?

Here are 5 related questions:

  1. How do you handle inequalities with fractions?
  2. What is the significance of multiplying by the least common denominator (LCD)?
  3. Can this inequality solution be plotted on a number line?
  4. How do we handle inequalities when multiplying or dividing by negative numbers?
  5. What happens when the inequality involves absolute values?

Tip: Always check for sign changes when multiplying or dividing both sides of an inequality by negative values.

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Math Problem Analysis

Mathematical Concepts

Algebra
Inequalities
Fractions

Formulas

Distributive property: a(b + c) = ab + ac
Solving linear inequalities
Clearing fractions by multiplying both sides by the least common denominator (LCD)

Theorems

Basic inequality solving rules
Multiplication property of inequalities

Suitable Grade Level

Grades 10-12