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The problem asks to solve the inequality:

\[
12x - 7 \leq 7
\]

### Step-by-Step Solution:

1. **Add 7 to both sides** of the inequality to isolate the term with \(x\) on the left-hand side:
   \[
   12x \leq 7 + 7
   \]
   \[
   12x \leq 14
   \]

2. **Divide both sides by 12** to solve for \(x\):
   \[
   x \leq \frac{14}{12}
   \]
   Simplifying the fraction:
   \[
   x \leq \frac{7}{6}
   \]

Thus, the solution is:
\[
x \leq \frac{7}{6}
\]

Let me know if you need further clarification or have any other questions!

Here are 5 related questions for practice:
1. Solve \(3x - 4 \leq 10\).
2. Solve \(5x + 2 > 12\).
3. What is the solution to \(7x + 3 \geq -4\)?
4. Solve for \(x\) in the inequality \(2x - 5 < 11\).
5. How do you solve \(6x + 4 \leq 2x + 8\)?

**Tip:** Always remember to reverse the inequality sign when multiplying or dividing both sides of an inequality by a negative number.

Learn how to solve the inequality 12x - 7 ≤ 7 with a step-by-step breakdown. Understand how to isolate variables, use basic algebraic principles, and solve inequalities. This explanation is perfect for students in Grades 6-8.

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