https://file.aiquickdraw.com/mathbot/file/1726237115926p5ol38qz.jpg

The inequality in the image is:

\[
12x + 3 \leq 5
\]

### To solve this inequality:

1. **Subtract 3 from both sides:**
   \[
   12x \leq 5 - 3
   \]
   \[
   12x \leq 2
   \]

2. **Divide both sides by 12:**
   \[
   x \leq \frac{2}{12}
   \]
   \[
   x \leq \frac{1}{6}
   \]

### Final solution:
\[
x \leq \frac{1}{6}
\]

This means that any value of \(x\) that is less than or equal to \(\frac{1}{6}\) satisfies the inequality.

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Do you want more details or have any questions?

Here are 5 related questions you might find helpful:
1. How would the solution change if the inequality was \(12x + 3 \geq 5\)?
2. How do you graph the solution of this inequality on a number line?
3. What happens if you multiply or divide both sides of an inequality by a negative number?
4. How do you solve compound inequalities that involve "and" or "or" conditions?
5. Can inequalities have more than one solution, and how do you represent them?

**Tip:** Always remember to reverse the inequality symbol when multiplying or dividing both sides by a negative number.

Find the solutions of the following inequality: 12x + 3 ≤ 5

Learn how to solve the inequality 12x + 3 ≤ 5 step by step. This solution covers algebraic inequality concepts suitable for students in Grades 9-10.

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