This is a right triangle where one leg is 15 units, one angle is $70^\circ$, and the hypotenuse is marked as $x$. Let's solve for $x$ using trigonometric ratios.

The hypotenuse $x$ can be calculated using the sine function:

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}$

Here:

• Opposite = $15$
• Hypotenuse = $x$
• Angle = $70^\circ$

Substitute into the formula:

$\sin(70^\circ) = \frac{15}{x}$

Rearrange for $x$:

$x = \frac{15}{\sin(70^\circ)}$

Step 1: Calculate $\sin(70^\circ)$

Using a calculator: $\sin(70^\circ) \approx 0.9397$

Step 2: Solve for $x$

$x = \frac{15}{0.9397} \approx 15.96$

Final Answer:

$x \approx 15.96 \, \text{units}$

Would you like further details or clarification on this? Here are five related questions to explore:

1. How can we solve for the other leg of the triangle if needed?
2. What is the relationship between sine, cosine, and tangent for right triangles?
3. How do trigonometric ratios apply to real-world problems?
4. Can you use the Pythagorean Theorem to verify this solution?
5. What happens if the angle changes to $60^\circ$? How does the hypotenuse change?

Tip: Always double-check calculations involving trigonometric functions to ensure proper angle mode (degrees/radians) on your calculator!