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The equation provided is:

\[ 9y - y = 16 \]

To solve for \( y \):

1. Combine like terms on the left-hand side of the equation:
   \[ (9y - y) = 8y \]

   So, the equation simplifies to:
   \[ 8y = 16 \]

2. To solve for \( y \), divide both sides of the equation by 8:
   \[ y = \frac{16}{8} \]

3. Simplify the right-hand side:
   \[ y = 2 \]

So, the solution is \( y = 2 \).

Would you like more details on any part of this solution, or do you have any other questions?

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Here are some related questions for further exploration:

1. What would be the solution if the equation was \( 9y - 2y = 18 \)?
2. How would the solution change if the equation was \( 9y - y = 10 \) instead?
3. What steps would you take if the equation had a constant on the left side, like \( 9y - y + 3 = 16 \)?
4. Can you solve for \( y \) if the equation was \( 9y - y = 0 \)?
5. What happens if \( y \) is a fraction, say \( 9y - y = \frac{1}{2} \)?

**Tip:** Always combine like terms first when solving linear equations to simplify the equation before solving for the variable.

Learn how to solve the linear equation 9y - y = 16 with a clear step-by-step solution. This problem is suitable for students in Grades 6-8 and covers essential algebraic concepts like combining like terms and solving linear equations.

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