The equation provided is:

$9y - y = 16$

To solve for $y$:

1. Combine like terms on the left-hand side of the equation: $(9y - y) = 8y$

   So, the equation simplifies to: $8y = 16$

2. To solve for $y$, divide both sides of the equation by 8: $y = \frac{16}{8}$

3. Simplify the right-hand side: $y = 2$

So, the solution is $y = 2$.

Would you like more details on any part of this solution, or do you have any other questions?

Here are some related questions for further exploration:

1. What would be the solution if the equation was $9y - 2y = 18$?
2. How would the solution change if the equation was $9y - y = 10$ instead?
3. What steps would you take if the equation had a constant on the left side, like $9y - y + 3 = 16$?
4. Can you solve for $y$ if the equation was $9y - y = 0$?
5. What happens if $y$ is a fraction, say $9y - y = \frac{1}{2}$?

Tip: Always combine like terms first when solving linear equations to simplify the equation before solving for the variable.