https://file.aiquickdraw.com/mathbot/file/1725858716902ckst91s4.jpg

The equation provided in the image is:

\[
V = \frac{1}{3} B h
\]

where \( V \) represents volume, \( B \) represents the base area, and \( h \) is the height. We need to solve for \( h \).

### Step-by-step Solution:

1. Start with the given equation:
   \[
   V = \frac{1}{3} B h
   \]

2. To eliminate the fraction, multiply both sides by 3:
   \[
   3V = B h
   \]

3. Now, solve for \( h \) by dividing both sides by \( B \):
   \[
   h = \frac{3V}{B}
   \]

Thus, the correct solution is:

\[
h = \frac{3V}{B}
\]

From the options given in the image, the correct answer is the third one:
\[
h = \frac{3V}{B}
\]

Let me know if you want more details or have any other questions!

Here are 5 related questions for further practice:
1. What is the value of \( h \) if \( V = 27 \, \text{units}^3 \) and \( B = 9 \, \text{units}^2 \)?
2. How would the equation change if instead of \( \frac{1}{3} \), the constant was \( \frac{1}{2} \)?
3. What does the base area \( B \) represent in real-world applications?
4. Can this formula be used to find the volume of a cylinder? Why or why not?
5. How does the volume change when both the base \( B \) and height \( h \) are doubled?

**Tip:** When solving for variables, always perform inverse operations systematically to isolate the unknown variable.

Solve the equation for the indicated variable: V = 1/3 * B * h; solve for h.

Learn how to solve for the variable h in the equation V = (1/3) * B * h. This problem involves algebraic manipulation and solving for a single variable. Suitable for students in Grades 7-9.

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