Let's solve the equation step by step.

You have the equation:

\[
\frac{5}{2} - 2g = \frac{5}{2}g - 3 + g
\]

### Step 1: Combine like terms on the right-hand side
The right-hand side has two terms involving \( g \), which can be combined.

\[
\frac{5}{2} - 2g = \frac{5}{2}g + g - 3
\]

Combine \( \frac{5}{2}g + g \) (note that \( g = 1g \)):

\[
\frac{5}{2} - 2g = \frac{7}{2}g - 3
\]

### Step 2: Move all terms involving \( g \) to one side
Add \( 2g \) to both sides to bring all \( g \)-terms to the right side:

\[
\frac{5}{2} = \frac{7}{2}g + 2g - 3
\]

Now, express \( 2g \) with a common denominator:

\[
2g = \frac{4}{2}g
\]

So:

\[
\frac{5}{2} = \frac{7}{2}g + \frac{4}{2}g - 3
\]

### Step 3: Combine \( g \)-terms on the right side
\[
\frac{5}{2} = \frac{11}{2}g - 3
\]

### Step 4: Move the constant term to the left side
Add 3 to both sides to isolate the \( g \)-terms on the right:

\[
\frac{5}{2} + 3 = \frac{11}{2}g
\]

Convert 3 to have a denominator of 2:

\[
\frac{5}{2} + \frac{6}{2} = \frac{11}{2}g
\]

\[
\frac{11}{2} = \frac{11}{2}g
\]

### Step 5: Solve for \( g \)
Since the numerators are equal, \( g \) must equal 1:

\[
g = 1
\]

The solution is \( g = 1 \).

---

Do you want further details or have any questions?

Here are 5 related questions for further practice:
1. Solve \( 4x - 7 = 2x + 5 \) for \( x \).
2. Solve \( 3g - \frac{1}{2}g = 7 + g \) for \( g \).
3. Solve \( \frac{2}{3}x - 5 = \frac{1}{3}x + 2 \).
4. Simplify and solve \( 6x + 4 = 8x - 10 \) for \( x \).
5. Solve \( 5 - 2y = 3y + 1 \) for \( y \).

**Tip**: Always combine like terms and simplify as much as possible before moving terms across the equation.

Solve for g. 5/2 – 2g = 5/2 g – 3 + g

Learn how to solve the algebraic equation 5/2 – 2g = 5/2 g – 3 + g. This problem covers key algebraic concepts such as combining like terms, isolating variables, and balancing equations. Suitable for students in Grades 8-10.

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