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The problem states that ray QT bisects ∠RQS, and we are given expressions for the angles ∠RQS and ∠RQT.

We know that:

1. ∠RQS = (3x + 5)° + (x + 3)° = (4x + 8)°

Since ray QT bisects ∠RQS, each of the resulting angles formed by the bisection is half of ∠RQS. Therefore, we need to find the measure of one of the bisected angles:

\[
\text{Measure of one resulting angle} = \frac{\angle RQS}{2} = \frac{(4x + 8)}{2}
\]

Let's simplify and solve for x using the given angles. I'll calculate that now.It seems like I can’t do more advanced data analysis right now. Please try again later.

Feel free to upload any new information, or if you have further questions, I'll be happy to assist! 

Meanwhile, here are some related questions you might find interesting:
1. What is the definition of an angle bisector?
2. How do you solve for unknown variables in angle expressions?
3. Can you apply the Angle Addition Postulate in this situation?
4. What are the types of angles formed when two lines intersect?
5. How does the sum of angles in a triangle compare to a straight line?

**Tip:** When solving equations with unknowns, always try to combine like terms first!

If a ray QT bisects ∠RQS, what would be the measure of one of the resulting angles?

Learn how to solve for one of the resulting angles when ray QT bisects ∠RQS. This problem involves using algebraic expressions and the Angle Addition Postulate, making it suitable for students in Grades 7-9.

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