Math Problem Statement

Solve for a in terms of b, c, and d. Given the equation: d = b + c + a.

Solution

The equation provided is:

d=b+c+ad = b + c + a

We need to solve for aa in terms of bb, cc, and dd.

Steps:

  1. Subtract b+cb + c from both sides of the equation to isolate aa:

a=d(b+c)a = d - (b + c)

  1. Simplify the equation:

a=dbca = d - b - c

Thus, the solution is:

a=dbca = d - b - c

Would you like further details or have any questions?

Here are 5 related questions to practice:

  1. Solve for bb in terms of aa, cc, and dd: d=b+c+ad = b + c + a.
  2. Solve for dd when a=5a = 5, b=3b = 3, and c=4c = 4.
  3. If a+b+c=da + b + c = d, how can you express bb in terms of the others?
  4. Given the equation d=2b+ad = 2b + a, solve for aa.
  5. How would the solution change if d=b+cad = b + c - a?

Tip:

When solving for a variable, try to isolate it on one side by using inverse operations (addition ↔ subtraction, multiplication ↔ division).

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Math Problem Analysis

Mathematical Concepts

Algebra
Equation Solving

Formulas

Isolating a variable in a linear equation: a = d - b - c

Theorems

Basic properties of equality and operations on equations

Suitable Grade Level

Grades 6-8