y  =  √ A x 

If y = 43.0 and x = 10.8, what is A?


We are given the equation \( y = \sqrt{A x} \), and we need to solve for \( A \) when \( y = 43.0 \) and \( x = 10.8 \).

1. Start by squaring both sides of the equation to eliminate the square root:

\[
y^2 = A x
\]

2. Substitute the known values of \( y = 43.0 \) and \( x = 10.8 \) into the equation:

\[
43.0^2 = A \times 10.8
\]

3. Simplify the left-hand side:

\[
1849 = A \times 10.8
\]

4. Solve for \( A \) by dividing both sides by 10.8:

\[
A = \frac{1849}{10.8}
\]

Now, I'll calculate the value of \( A \).The value of \( A \) is approximately \( 171.20 \).

Would you like more details or have any questions?

Here are 5 related questions you can explore:
1. How would the value of \( A \) change if \( x \) increases?
2. What happens to \( A \) if \( y \) is halved?
3. Can you solve for \( x \) given \( A \) and \( y \)?
4. How can this formula be applied in real-life situations?
5. What is the relationship between \( y \) and \( x \) when \( A \) is constant?

**Tip**: Always double-check the units in physics-related problems to ensure consistent calculations.

If y = 43.0 and x = 10.8, what is A in the equation y = √(A * x)?

Learn how to solve for A in the equation y = √(A * x) when y = 43.0 and x = 10.8. This problem involves key algebraic concepts such as square roots, solving for variables, and algebraic manipulation. Ideal for students in Grades 9-11.

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