Let's solve the expression step by step:

Given expression:

\[
-3(3 - 2) + (-9)(2)^3
\]

1. **Evaluate the expression inside the parentheses**:  
   \[
   3 - 2 = 1
   \]

2. **First multiplication**:  
   \[
   -3 \times 1 = -3
   \]

3. **Evaluate the exponent**:  
   \[
   2^3 = 2 \times 2 \times 2 = 8
   \]

4. **Second multiplication**:  
   \[
   (-9) \times 8 = -72
   \]

5. **Add the results**:  
   \[
   -3 + (-72) = -3 - 72 = -75
   \]

So, the final result is \(-75\).

Would you like more details or have any questions about this? Here are five related questions you might find interesting:

1. How do you solve expressions with multiple operations and parentheses?
2. How do you approach problems with both positive and negative exponents?
3. What are some techniques for simplifying complex arithmetic expressions?
4. How can you check your work when solving a multi-step problem?
5. What are the rules for combining like terms in algebraic expressions?

**Tip:** When dealing with exponents, always ensure you apply the exponent before multiplying by any coefficients outside the parentheses.

Learn how to solve the expression -3(3 - 2) + (-9)(2)^3 step-by-step with detailed explanations. This problem involves arithmetic operations, evaluating expressions within parentheses, and exponentiation. Suitable for students in Grades 6-8.

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