To solve the expression $(2y^2)(3y^3)(4y^5)$, follow these steps:

1. Multiply the coefficients: Multiply the numbers $2$, $3$, and $4$ together. $2 \times 3 \times 4 = 24$

2. Add the exponents of $y$: Add the exponents of $y$ (i.e., $2$, $3$, and $5$) because when you multiply powers with the same base, you add the exponents. $y^{2+3+5} = y^{10}$

3. Combine the results: Multiply the coefficient and the $y$ term together. $24y^{10}$

So, $(2y^2)(3y^3)(4y^5) = 24y^{10}$.

Would you like more details or have any questions about this process?

Here are 5 related questions you might find interesting:

1. What is the result of $(5x^3)(2x^4)$?
2. How do you simplify $(7y^3)(2y^2)(y)$?
3. What happens if the exponents are negative, for example, $(3y^{-2})(2y^4)$?
4. Can you expand $(x + y)^3$?
5. How do you handle multiplication of polynomials like $(x^2 + y^2)(x + y)$?

Tip: Remember that when multiplying terms with the same base, you simply add their exponents.