To solve the expression \((2y^2)(3y^3)(4y^5)\), follow these steps:

1. **Multiply the coefficients**: Multiply the numbers \(2\), \(3\), and \(4\) together.
   \[
   2 \times 3 \times 4 = 24
   \]

2. **Add the exponents of \(y\)**: Add the exponents of \(y\) (i.e., \(2\), \(3\), and \(5\)) because when you multiply powers with the same base, you add the exponents.
   \[
   y^{2+3+5} = y^{10}
   \]

3. **Combine the results**: Multiply the coefficient and the \(y\) term together.
   \[
   24y^{10}
   \]

So, \((2y^2)(3y^3)(4y^5) = 24y^{10}\).

Would you like more details or have any questions about this process? 

Here are 5 related questions you might find interesting:
1. What is the result of \((5x^3)(2x^4)\)?
2. How do you simplify \((7y^3)(2y^2)(y)\)?
3. What happens if the exponents are negative, for example, \((3y^{-2})(2y^4)\)?
4. Can you expand \((x + y)^3\)?
5. How do you handle multiplication of polynomials like \((x^2 + y^2)(x + y)\)?

**Tip:** Remember that when multiplying terms with the same base, you simply add their exponents.

Learn how to solve the expression (2y^2)(3y^3)(4y^5) with a detailed step-by-step solution. This problem covers algebraic concepts related to exponents. Suitable for students in Grades 7-9.

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