Math Problem Statement

Реши и объясни

Найдите значение выражения (2x - y) / (2x + y), если известно, что (4x^2 - 4xy + 3y^2) / (2y^2 + 2xy - 5x^2) = 1.

Solution

The given task asks to find the value of the expression:

2xy2x+y\frac{2x - y}{2x + y}

given the equation:

4x24xy+3y22y2+2xy5x2=1.\frac{4x^2 - 4xy + 3y^2}{2y^2 + 2xy - 5x^2} = 1.

Step 1: Analyze the given equation

The equation provided is:

4x24xy+3y22y2+2xy5x2=1.\frac{4x^2 - 4xy + 3y^2}{2y^2 + 2xy - 5x^2} = 1.

To simplify, multiply both sides of the equation by the denominator:

4x24xy+3y2=2y2+2xy5x2.4x^2 - 4xy + 3y^2 = 2y^2 + 2xy - 5x^2.

Step 2: Rearrange the terms

Now, move all terms to one side:

4x24xy+3y22y22xy+5x2=0.4x^2 - 4xy + 3y^2 - 2y^2 - 2xy + 5x^2 = 0.

Simplify:

(4x2+5x2)+(4xy2xy)+(3y22y2)=0,(4x^2 + 5x^2) + (-4xy - 2xy) + (3y^2 - 2y^2) = 0,

which simplifies further to:

9x26xy+y2=0.9x^2 - 6xy + y^2 = 0.

Step 3: Factor the equation

We can attempt factoring the expression 9x26xy+y29x^2 - 6xy + y^2. Notice that this is a perfect square trinomial:

(3xy)2=0.(3x - y)^2 = 0.

Thus, we have:

3xy=0,3x - y = 0,

which simplifies to:

y=3x.y = 3x.

Step 4: Substitute into the required expression

Now, substitute y=3xy = 3x into the original expression 2xy2x+y\frac{2x - y}{2x + y}:

2x3x2x+3x=x5x=15.\frac{2x - 3x}{2x + 3x} = \frac{-x}{5x} = -\frac{1}{5}.

Final Answer:

The value of the expression is 15-\frac{1}{5}.

Would you like further details or have any questions?

Here are 5 questions for further exploration:

  1. How does factoring help solve quadratic equations like in this example?
  2. What other methods could be used to solve 9x26xy+y2=09x^2 - 6xy + y^2 = 0?
  3. How can this process be generalized for more complex expressions?
  4. Why is it important to check whether a trinomial is a perfect square?
  5. Can you think of similar problems involving substitution techniques?

Tip: Always check if an expression can be factored into a perfect square to simplify solving equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factoring

Formulas

Factoring of quadratic equations
Solving equations by substitution

Theorems

Perfect square trinomial theorem
Factoring quadratics

Suitable Grade Level

Grades 9-11