Let's break down and solve the expression step by step:

\[
124 \div 16 - 34 + 124 \div (6 + 12 \div 3 - 6)
\]

### Step 1: Solve divisions inside the parentheses first.
- \(12 \div 3 = 4\)

So, the expression inside the parentheses becomes:

\[
6 + 4 - 6 = 4
\]

### Step 2: Replace the parentheses with the result and solve the divisions.
Now the expression is:

\[
124 \div 16 - 34 + 124 \div 4
\]

Let's solve each division:

- \(124 \div 16 = 7.75\)
- \(124 \div 4 = 31\)

### Step 3: Replace the division results and simplify.
Now the expression is:

\[
7.75 - 34 + 31
\]

### Step 4: Perform the additions and subtractions in order.
- \(7.75 - 34 = -26.25\)
- \(-26.25 + 31 = 4.75\)

### Final result:
\[
\boxed{4.75}
\]

Would you like more details or have any questions?

Here are 5 related questions for practice:
1. Solve \(150 \div 25 - 40 + 150 \div (5 + 15 \div 5 - 5)\).
2. Simplify \(200 \div 20 - 50 + 200 \div (4 + 16 \div 4 - 4)\).
3. What is the result of \(60 \div 15 - 12 + 60 \div (8 + 24 \div 8 - 8)\)?
4. Calculate \(180 \div 12 - 20 + 180 \div (9 + 27 \div 9 - 9)\).
5. Solve \(144 \div 18 - 36 + 144 \div (7 + 14 \div 7 - 7)\).

**Tip**: Always perform operations inside parentheses first and remember the order of operations (PEMDAS: Parentheses, Exponents, Multiplication/Division, Addition/Subtraction).

124 ÷ 16 - 34 + 124 ÷ (6 + 12 ÷ 3 - 6)

Learn how to solve the expression 124 ÷ 16 - 34 + 124 ÷ (6 + 12 ÷ 3 - 6) using the order of operations (PEMDAS). This problem involves division, addition, and subtraction, making it perfect for students in Grades 6-8.

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