To solve the equation \( \frac{z}{3} - (-14) = 17 \), follow these steps:

1. **Simplify the double negative**: 
   \[
   \frac{z}{3} + 14 = 17
   \]

2. **Subtract 14 from both sides** to isolate the term with \( z \):
   \[
   \frac{z}{3} = 3
   \]

3. **Multiply both sides by 3** to solve for \( z \):
   \[
   z = 3 \times 3
   \]

   \[
   z = 9
   \]

### Final Answer: \( z = 9 \)

Would you like more details on any step or have other questions?

Here are 5 related questions:
1. How would you solve \( \frac{x}{5} + 10 = 25 \)?
2. What if the equation was \( \frac{z}{4} - (-7) = 5 \)?
3. How do you handle an equation like \( \frac{z}{2} - 3 = 8 \)?
4. What are the steps to isolate \( z \) in \( \frac{z}{6} + 9 = 12 \)?
5. How do you solve equations involving fractions on both sides, such as \( \frac{z}{4} = \frac{3}{2} \)?

**Tip**: Always watch out for double negatives in equations, as they can be simplified to addition.

This page provides a step-by-step guide to solve the linear equation z/3 - (-14) = 17. Learn to simplify double negatives, isolate the variable, and solve for z. This algebraic problem is ideal for students in Grades 6-8, covering key concepts such as handling negative signs and properties of equality.

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