$$  $$If $$ \sqrt{x} $$$$ +6=16 $$then x could equal

Given the equation $\sqrt{x} + 6 = 16$, let's solve for $x$ step by step:

1. **Isolate the square root**: 
   \[
   \sqrt{x} = 16 - 6
   \]
   \[
   \sqrt{x} = 10
   \]

2. **Square both sides** to eliminate the square root:
   \[
   (\sqrt{x})^2 = 10^2
   \]
   \[
   x = 100
   \]

So, $x$ could equal 100.

Would you like further details or have any questions? Here are some related questions to consider:

1. How do you isolate a variable when solving an equation?
2. What would happen if the equation were $\sqrt{x} + 6 = -16$?
3. How do you check if your solution is correct?
4. What are some potential extraneous solutions when squaring both sides?
5. What if the equation were $\sqrt{x} - 6 = 16$?
6. How does squaring affect the domain of the original equation?
7. What steps are necessary to solve an equation with multiple square roots?
8. What are some common mistakes when solving equations involving square roots?

**Tip:** Always remember to square both sides carefully and check the final solution in the original equation to avoid extraneous solutions.

Learn how to solve the equation sqrt(x) + 6 = 16 step-by-step with a detailed explanation. This problem involves isolating the square root and squaring both sides to find the value of x. Suitable for students in Grades 7-9.

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