Filbert the cat eats twice the amount of food as another cat, Kiko.

If together they eat three-quarters of one cup of cat food at each meal, which of the following equations will give you the number of cups, x, that Kiko eats at each meal?

A.)
3 x equals 3 over 4

B.)
3 over 4 x equals 2

C.)
2 x equals 3 over 4

D.)
3 over 4 x equals 3

Let's analyze the problem step by step.

We have two cats: Filbert and Kiko. Filbert eats twice as much as Kiko. Let's denote the amount of food Kiko eats as \( x \) cups. Since Filbert eats twice as much as Kiko, the amount of food Filbert eats would be \( 2x \) cups.

The total amount of food they eat together is given as \( \frac{3}{4} \) cup. So, the equation representing this situation is:

\[
x + 2x = \frac{3}{4}
\]

This simplifies to:

\[
3x = \frac{3}{4}
\]

So, the correct equation that gives you the number of cups \( x \) that Kiko eats at each meal is:

**Answer: A.) \( 3x = \frac{3}{4} \)**

Would you like more details or have any questions?

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Here are 5 related questions for further exploration:

1. How much does Filbert eat if Kiko eats 1/4 cup?
2. If Kiko eats 1/3 cup, how much do they eat together?
3. How would the equation change if Filbert ate three times as much as Kiko?
4. If they ate a total of 1 cup together, how much would Kiko eat?
5. How would the equation look if Kiko ate twice as much as Filbert?

**Tip:** When setting up equations, make sure to clearly define your variables and their relationships. This helps in forming accurate mathematical models.

Learn how to solve the equation related to Filbert and Kiko's food consumption problem, where Filbert eats twice as much as Kiko. Understand the mathematical relationship and find the solution for the amount of food Kiko eats per meal. Suitable for students in Grades 6-8.

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