Math Problem Statement

Solve the equation using any convenient method. a2x2 – b2 = 0, a and b are real numbers x = (smaller value when a and b are positive values) x = (larger value when a and b are positive values)

Solution

The equation given is:

a2x2b2=0a^2x^2 - b^2 = 0

We can solve this equation using the following steps:

Step 1: Isolate x2x^2

a2x2=b2a^2x^2 = b^2

Step 2: Divide both sides by a2a^2

x2=b2a2x^2 = \frac{b^2}{a^2}

Step 3: Take the square root of both sides

x=±bax = \pm \frac{b}{a}

This gives two possible solutions for xx:

x=baorx=bax = \frac{b}{a} \quad \text{or} \quad x = -\frac{b}{a}

Step 4: Determine the smaller and larger values when a>0a > 0 and b>0b > 0

  • Smaller value: x=bax = -\frac{b}{a}
  • Larger value: x=bax = \frac{b}{a}

Final Answer:

  • Smaller value of xx: ba-\frac{b}{a}
  • Larger value of xx: ba\frac{b}{a}

Would you like any further details on this solution, or do you have any questions?

Here are 5 related questions to consider:

  1. How does the solution change if aa or bb are negative?
  2. Can this equation be solved graphically? What would the graph look like?
  3. What is the significance of the roots in a physical context, such as in motion problems?
  4. How does the discriminant confirm the nature of the roots?
  5. What happens if a=0a = 0 or b=0b = 0?

Tip: Always check for special cases like zero values or undefined terms when solving equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations

Formulas

Quadratic equation formula ax^2 + bx + c = 0

Theorems

Quadratic formula

Suitable Grade Level

Grades 10-12