Let's solve the equation:

\[
\frac{X - 5}{5} = \frac{x - 3}{5}
\]

1. **Eliminate the fractions** by multiplying both sides of the equation by 5:

\[
X - 5 = x - 3
\]

2. **Simplify** the equation by isolating \( X \) on one side:

\[
X - x = -3 + 5
\]

\[
X - x = 2
\]

So, the solution is:

\[
X - x = 2
\]

This equation indicates that \( X \) is always 2 units greater than \( x \).

Would you like further details or have any questions? Here are some related questions to explore:

1. What would happen if \( X = x + 2 \) were substituted back into the original equation?
2. How would the solution change if the equation was \( \frac{X - 5}{3} = \frac{x - 3}{4} \)?
3. What are some examples of values of \( X \) and \( x \) that satisfy \( X - x = 2 \)?
4. How do we solve an equation where the fractions have different denominators?
5. Can you solve the equation if there were additional terms added to both sides, like \( \frac{X - 5}{5} + 1 = \frac{x - 3}{5} + 2 \)?

**Tip:** Always start by eliminating fractions in an equation to simplify the solving process.

Learn how to solve the equation (X - 5)/5 = (x - 3)/5 with a detailed step-by-step solution. This problem involves eliminating fractions and simplifying algebraic expressions. Suitable for students in Grades 6-8.

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