To solve the equation \( 7(x + 3) = 9x + 30 \), let's go through the steps:

1. **Distribute the 7 on the left-hand side**:
   \[
   7(x + 3) = 7 \cdot x + 7 \cdot 3 = 7x + 21
   \]
   So the equation becomes:
   \[
   7x + 21 = 9x + 30
   \]

2. **Move the variable terms to one side**:
   Subtract \( 7x \) from both sides:
   \[
   21 = 2x + 30
   \]

3. **Isolate the variable**:
   Subtract 30 from both sides:
   \[
   21 - 30 = 2x
   \]
   Simplifying:
   \[
   -9 = 2x
   \]

4. **Solve for \( x \)**:
   Divide both sides by 2:
   \[
   x = \frac{-9}{2}
   \]
   Simplifying:
   \[
   x = -\frac{9}{2} \text{ or } x = -4.5
   \]

So, the solution is \( x = -4.5 \).

Would you like more details on any step, or do you have any questions?

Here are some related questions you might find interesting:
1. How do you solve similar linear equations with fractions?
2. What happens if you have an equation with variables on both sides and you can't isolate one?
3. How do you check if your solution is correct?
4. How would the solution change if the equation was \( 7(x + 3) = 9x + 21 \)?
5. What is the method for solving quadratic equations?

**Tip:** Always double-check your solution by substituting it back into the original equation!

Learn how to solve the equation 7(x + 3) = 9x + 30 with detailed steps and explanations. This problem involves applying the distributive property and isolating variables. Suitable for students in Grades 7-9.

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