Let's solve the equation \(6 = 1 - 2n + 5\).

### Step 1: Simplify the equation
Combine the constants on the right side:
\[
6 = 1 + 5 - 2n
\]
\[
6 = 6 - 2n
\]

### Step 2: Isolate the term with the variable
Subtract 6 from both sides to isolate the term involving \(n\):
\[
6 - 6 = -2n
\]
\[
0 = -2n
\]

### Step 3: Solve for \(n\)
Divide both sides by \(-2\) to solve for \(n\):
\[
n = \frac{0}{-2}
\]
\[
n = 0
\]

So, the solution is \(n = 0\).

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:
1. What happens if the equation is slightly altered to \(6 = 1 - 2n + 4\)?
2. How do you solve the equation \(5n + 3 = 2n + 9\)?
3. Can you solve \(2n + 3 = n + 7\) and explain the steps?
4. What if the equation were \(6 = 1 - 2n - 5\), how would that change the solution?
5. How would you approach solving \(3n - 4 = 2 - n\)?

**Tip:** When solving linear equations, always aim to isolate the variable on one side of the equation.

Learn how to solve the equation 6 = 1 - 2n + 5 with a detailed step-by-step solution. This problem involves linear equations and includes isolating variables and basic arithmetic operations. Suitable for students in Grades 6-8.

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