Let's solve the equation \( 4u = 45 - u \).

### Step 1: Combine like terms.
Add \( u \) to both sides of the equation to get all the \( u \) terms on one side:

\[
4u + u = 45
\]

This simplifies to:

\[
5u = 45
\]

### Step 2: Solve for \( u \).
Divide both sides by 5:

\[
u = \frac{45}{5} = 9
\]

So, the solution is \( u = 9 \).

Would you like more details or have any questions? Here are some related questions you might find interesting:

1. How would the solution change if the equation were \( 4u = 50 - u \)?
2. What if the equation were \( 4u + 2 = 45 - u \)?
3. Can you solve \( 3u = 60 - 2u \) using similar steps?
4. How do you solve the equation if it is in the form \( au + b = cu + d \)?
5. What are the steps to solve a quadratic equation like \( u^2 - 4u + 4 = 0 \)?

**Tip:** When solving equations, always aim to isolate the variable on one side to make the solution straightforward.

Learn how to solve the equation 4u = 45 - u with a step-by-step solution. This problem covers fundamental algebraic concepts, including solving linear equations and isolating variables. Suitable for students in Grades 7-9.

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