Let's solve the equation $2x - 5 = -3(2x + 3)$.

Step 1: Distribute the $-3$ on the right side

$2x - 5 = -6x - 9$

Step 2: Move all the $x$ terms to one side and the constants to the other side

Add $6x$ to both sides: $2x + 6x - 5 = -9$ $8x - 5 = -9$

Step 3: Add 5 to both sides to isolate the $x$ term

$8x = -9 + 5$ $8x = -4$

Step 4: Solve for $x$ by dividing both sides by 8

$x = \frac{-4}{8}$ $x = -\frac{1}{2}$

So, the solution is $x = -\frac{1}{2}$.

Would you like more details, or do you have any questions?

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Here are five related questions:

1. How would the solution change if the equation were $2x - 5 = -3(2x - 3)$?
2. What is the value of $x$ if the equation is $2x + 5 = -3(2x + 3)$?
3. Can you solve $4x - 7 = -2(2x + 5)$ for $x$?
4. What happens if you substitute $x = -\frac{1}{2}$ back into the original equation?
5. How would you solve $3x - 9 = -4(2x + 6)$?

Tip: When dealing with negative signs in front of parentheses, be careful to distribute the sign correctly to avoid errors.