Let's solve the equation \( 12(3s - 4 - 3s) = 2(2s + 2) + 2s + 2 \).

### Step 1: Simplify both sides of the equation

First, simplify the expression inside the parentheses on the left side:

\[
12(3s - 4 - 3s)
\]

Notice that \( 3s - 3s = 0 \), so the left side simplifies to:

\[
12(-4) = -48
\]

Now, simplify the right side:

\[
2(2s + 2) + 2s + 2
\]

Distribute the \( 2 \) across \( 2s + 2 \):

\[
2 \times 2s + 2 \times 2 = 4s + 4
\]

So, the right side becomes:

\[
4s + 4 + 2s + 2
\]

Combine like terms:

\[
6s + 6
\]

### Step 2: Set the simplified expressions equal to each other

Now, we have the simplified equation:

\[
-48 = 6s + 6
\]

### Step 3: Solve for \( s \)

First, isolate the term involving \( s \) by subtracting 6 from both sides:

\[
-48 - 6 = 6s
\]

This simplifies to:

\[
-54 = 6s
\]

Next, divide both sides by 6 to solve for \( s \):

\[
s = \frac{-54}{6} = -9
\]

So, the solution is:

\[
\boxed{s = -9}
\]

Would you like more details or have any questions?

### Related Questions
1. What would change if the equation was \( 12(3s - 4 + 3s) = 2(2s + 2) + 2s + 2 \)?
2. How would you solve \( 5(2x - 3) = 3(x + 4) + 2x \)?
3. Can you simplify \( 3(4y -

Learn how to solve the equation 12(3s - 4 - 3s) = 2(2s + 2) + 2s + 2 step-by-step. This problem involves simplifying expressions, distributing terms, and solving linear equations. Suitable for high school students.

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