To solve the equation \( \frac{1}{6}c + 20 = 33 \) for \( c \), follow these steps:

### Step 1: Subtract 20 from both sides of the equation.
\[
\frac{1}{6}c + 20 - 20 = 33 - 20
\]
\[
\frac{1}{6}c = 13
\]

### Step 2: Multiply both sides of the equation by 6 to solve for \( c \).
\[
c = 13 \times 6
\]
\[
c = 78
\]

So, the solution is \( c = 78 \).

Would you like more details or have any questions?

Here are 5 related questions:
1. How would the solution change if the equation was \( \frac{1}{6}c + 20 = 40 \)?
2. What are the steps to isolate the variable in a fraction equation?
3. How do you solve \( 1/6c = 13 - 20 \)?
4. What happens if you multiply both sides of an equation by the denominator first?
5. Can you solve for \( c \) in the equation \( \frac{1}{6}(c + 10) = 33 \)?

**Tip:** When dealing with fractions in equations, it's often helpful to eliminate the fraction by multiplying both sides by the denominator.

Learn how to solve the equation (1/6)c + 20 = 33 step-by-step with a detailed explanation and solution. This problem covers solving equations involving fractions and is suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation