To solve the equation \( 0.86 = \log(x) \), we need to understand that the logarithm function here is most likely a common logarithm, which means it has a base of 10. So, the equation can be rewritten as:

\[
0.86 = \log_{10}(x)
\]

To solve for \( x \), we can use the definition of the logarithm: if \( \log_{10}(x) = y \), then \( x = 10^y \). Applying this definition to our equation:

\[
x = 10^{0.86}
\]

Now, let's calculate \( 10^{0.86} \):

\[
x \approx 10^{0.86} \approx 7.24
\]

So, the solution is:

\[
x \approx 7.24
\]

Would you like further details or have any questions?

Here are some related questions you might be interested in exploring:

1. What is the natural logarithm, and how does it differ from the common logarithm?
2. How do you solve logarithmic equations with different bases?
3. What are the properties of logarithms, such as the product, quotient, and power rules?
4. How can logarithmic functions be used to solve real-world problems?
5. How do you graph logarithmic functions, and what are their key features?

**Tip:** Remember, \( \log_{10}(x) \) is commonly written as \( \log(x) \) in most contexts, whereas the natural logarithm, \( \log_e(x) \), is written as \( \ln(x) \).

Learn how to solve the equation 0.86 = log(x) using logarithmic definitions and calculations. This problem covers logarithmic concepts with a common base and involves calculating logarithmic values. Suitable for students in Grades 10-12.

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