Math Problem Statement

(x 2 +y 2 +1)dx−(xy+y)dy=0 solve by integrating factor

Solution

To solve the given differential equation:

(x2+y2+1)dx(xy+y)dy=0(x^2 + y^2 + 1)dx - (xy + y)dy = 0

Step 1: Check if the equation is exact

The general form of an exact equation is: M(x,y)dx+N(x,y)dy=0M(x, y)dx + N(x, y)dy = 0 where M=x2+y2+1M = x^2 + y^2 + 1 and N=(xy+y)N = -(xy + y).

To check for exactness, compute: My=y(x2+y2+1)=2y\frac{\partial M}{\partial y} = \frac{\partial}{\partial y}(x^2 + y^2 + 1) = 2y Nx=x((xy+y))=y\frac{\partial N}{\partial x} = \frac{\partial}{\partial x}(-(xy + y)) = -y

Since MyNx\frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x}, the equation is not exact.


Step 2: Find the integrating factor

We try to identify an integrating factor. An often-used integrating factor for such equations is a function of xx or yy. Testing for μ(y)=y1\mu(y) = y^{-1}, multiply through by μ(y)\mu(y):

1y[(x2+y2+1)dx(xy+y)dy]=0\frac{1}{y}[(x^2 + y^2 + 1)dx - (xy + y)dy] = 0

This simplifies to: (x2y+y+1y)dx(x+1)dy=0\left(\frac{x^2}{y} + y + \frac{1}{y}\right)dx - \left(x + 1\right)dy = 0


Step 3: Check if the new equation is exact

Now let: M=x2y+y+1y,N=(x+1)M = \frac{x^2}{y} + y + \frac{1}{y}, \quad N = -(x + 1)

Compute: My=y(x2y+y+1y)=x2y2+11y2\frac{\partial M}{\partial y} = \frac{\partial}{\partial y}\left(\frac{x^2}{y} + y + \frac{1}{y}\right) = -\frac{x^2}{y^2} + 1 - \frac{1}{y^2} Nx=x((x+1))=1\frac{\partial N}{\partial x} = \frac{\partial}{\partial x}(-(x + 1)) = -1

Since MyNx\frac{\partial M}{\partial y} \neq \frac{\partial N}{\partial x}, the equation is still not exact.


Step 4: Alternative integrating factor

A more general form of integrating factor might be a function of both xx and yy. If μ=1x2+y2+1\mu = \frac{1}{x^2 + y^2 + 1}, multiplying the original equation by this factor yields:

1x2+y2+1[(x2+y2+1)dx(xy+y)dy]=0\frac{1}{x^2 + y^2 + 1}[(x^2 + y^2 + 1)dx - (xy + y)dy] = 0

Simplifying: dxxy+yx2+y2+1dy=0dx - \frac{xy + y}{x^2 + y^2 + 1}dy = 0

Now, this equation can be integrated directly.


Step 5: Solve the simplified equation

Rewrite as: dydx=xy+yx2+y2+1\frac{dy}{dx} = \frac{xy + y}{x^2 + y^2 + 1}

This is separable if simplified further or solved using substitution methods depending on the specific context.


Would you like me to proceed with a substitution, or clarify any steps so far?


Related Questions:

  1. What is the general process for checking exactness in differential equations?
  2. How do we determine an appropriate integrating factor for a given equation?
  3. Can this equation be solved directly without an integrating factor?
  4. What substitution techniques are commonly used in equations involving x2+y2+1x^2 + y^2 + 1?
  5. How can symmetry in the equation help simplify the solving process?

Tip:

For non-exact equations, always test simple integrating factors (xx-dependent, yy-dependent, or proportional to a function of both xx and yy) before resorting to more complex transformations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Differential Equations
Exact Equations
Integrating Factors

Formulas

Exactness condition: (∂M/∂y = ∂N/∂x)
Integrating factor formula (e.g., μ(y) = 1/y or μ = 1/(x^2 + y^2 + 1))

Theorems

Exactness Theorem
Methods for Non-Exact Differential Equations

Suitable Grade Level

Undergraduate Level (Calculus II or Differential Equations Course)