Math Problem Statement

If DF = 42, find DE. The line segment DF is composed of DE = 7x + 1 and EF = 4x - 3.

Solution

We are given that the total length DF=42DF = 42, and we need to find DEDE. The figure shows that the segment DFDF is composed of two smaller segments: DE=7x+1DE = 7x + 1 and EF=4x3EF = 4x - 3.

The sum of these two segments is equal to the total length:

DE+EF=DFDE + EF = DF

Substituting the expressions for DEDE and EFEF:

(7x+1)+(4x3)=42(7x + 1) + (4x - 3) = 42

Now, let's solve this equation for xx.

Step 1: Combine like terms

7x+4x+13=427x + 4x + 1 - 3 = 42 11x2=4211x - 2 = 42

Step 2: Solve for xx

Add 2 to both sides: 11x=4411x = 44

Divide by 11: x=4x = 4

Step 3: Find DEDE

Now that we know x=4x = 4, substitute this value back into the expression for DEDE: DE=7x+1=7(4)+1=28+1=29DE = 7x + 1 = 7(4) + 1 = 28 + 1 = 29

Thus, DE=29DE = 29.

Let me know if you need more details or have any questions! Here are some related questions to consider:

  1. What is the length of EFEF?
  2. How would the problem change if DFDF were a different length?
  3. Can we use a different method to solve for DEDE?
  4. What happens to DEDE if the values of xx are negative?
  5. How can you check if your solution is correct using different strategies?

Tip: Always check if the sum of segment lengths adds up to the total given length as a verification step!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Sum of segments: DE + EF = DF
Solving linear equations: ax + b = c

Theorems

-

Suitable Grade Level

Grades 7-9