Math Problem Statement

If α ≠ β and α = -2α + k, β = -2β + k, where k is a constant, then α³ + β³ = ?

Solution

We are given the following system of equations:

α=2α+k\alpha = -2\alpha + k β=2β+k\beta = -2\beta + k

We need to determine the value of α3+β3\alpha^3 + \beta^3.

Step 1: Solve for α\alpha and β\beta

Let’s first solve for α\alpha and β\beta from the equations provided.

For α\alpha:

α=2α+k\alpha = -2\alpha + k Add 2α2\alpha to both sides: α+2α=k\alpha + 2\alpha = k 3α=k3\alpha = k α=k3\alpha = \frac{k}{3}

For β\beta:

β=2β+k\beta = -2\beta + k Add 2β2\beta to both sides: β+2β=k\beta + 2\beta = k 3β=k3\beta = k β=k3\beta = \frac{k}{3}

Step 2: Find α3+β3\alpha^3 + \beta^3

Since α=β=k3\alpha = \beta = \frac{k}{3}, we have:

α3+β3=(k3)3+(k3)3\alpha^3 + \beta^3 = \left(\frac{k}{3}\right)^3 + \left(\frac{k}{3}\right)^3

This simplifies to:

α3+β3=2(k327)=2k327\alpha^3 + \beta^3 = 2 \left(\frac{k^3}{27}\right) = \frac{2k^3}{27}

Final Answer:

α3+β3=2k327\alpha^3 + \beta^3 = \frac{2k^3}{27}

Would you like a more detailed explanation or further clarification?

Here are 5 related questions to think about:

  1. How would the result change if αβ\alpha \neq \beta?
  2. What is the value of α2+β2\alpha^2 + \beta^2?
  3. Can this approach be generalized for any similar linear equation system?
  4. How would the equation change if the coefficients of α\alpha and β\beta were different?
  5. What is the interpretation of the result in terms of polynomial roots?

Tip: When dealing with equations involving variables, always solve the system step-by-step to isolate each variable.

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Math Problem Analysis

Mathematical Concepts

Algebra
System of Equations
Cubic Expressions

Formulas

Solving linear equations: ax + b = c
Cubic identity: a³ + b³ = (a + b)(a² - ab + b²)

Theorems

Properties of linear equations

Suitable Grade Level

Grades 10-12