Math Problem Statement

y = cos x solve using (275, 175) (400,275) (500,175)

Solution

To solve for the function y=cos(x)y = \cos(x) using the points (275,175)(275, 175), (400,275)(400, 275), and (500,175)(500, 175), we'll follow a systematic approach to determine the transformation of the cosine function that fits these points.

Step 1: Understand the Cosine Function

The general form of the cosine function is: y=acos(bx+c)+dy = a \cos(bx + c) + d where:

  • aa is the amplitude.
  • bb affects the period.
  • cc is the phase shift.
  • dd is the vertical shift.

Step 2: Analyze the Given Points

  • Point 1: (275,175)(275, 175)
  • Point 2: (400,275)(400, 275)
  • Point 3: (500,175)(500, 175)

Step 3: Identify Key Features from the Points

  • The yy value at (400,275)(400, 275) is the maximum, which suggests that this point represents the peak of the cosine wave.
  • The yy values at (275,175)(275, 175) and (500,175)(500, 175) are identical, suggesting that these points might correspond to positions where the cosine function has the same value, indicating symmetry.

Step 4: Determine the Amplitude and Vertical Shift

  1. Amplitude aa:

    • The amplitude is half the difference between the maximum and minimum yy values. a=2751752=50a = \frac{275 - 175}{2} = 50
  2. Vertical Shift dd:

    • The vertical shift is the average of the maximum and minimum yy values. d=275+1752=225d = \frac{275 + 175}{2} = 225

So far, our function is: y=50cos(bx+c)+225y = 50 \cos(bx + c) + 225

Step 5: Determine the Period and Phase Shift

  • The points (275,175)(275, 175) and (500,175)(500, 175) correspond to yy values equal to the mean, suggesting these points might be a quarter and three-quarters through the period of the cosine function.
  • The full period TT occurs between the first and third points, covering a 2π2\pi range.

Given:

  • T=500275=225T = 500 - 275 = 225

The period formula is: Period=2πb\text{Period} = \frac{2\pi}{b}

So: b=2π225b = \frac{2\pi}{225}

Step 6: Determine the Phase Shift cc

  • The maximum point occurs at x=400x = 400. For a standard cosine function, this corresponds to x=0x = 0, so the phase shift should make bx+c=0bx + c = 0 at x=400x = 400.

So: 4002π225+c=0400 \cdot \frac{2\pi}{225} + c = 0 c=800π225c = - \frac{800\pi}{225}

Final Equation

Putting everything together, the cosine function that fits the given points is approximately: y=50cos(2π225x800π225)+225y = 50 \cos\left(\frac{2\pi}{225} x - \frac{800\pi}{225}\right) + 225

Summary:

The final function is: y=50cos(2π225(x400))+225y = 50 \cos\left(\frac{2\pi}{225} (x - 400)\right) + 225 This function describes the cosine wave that fits the given points.

Do you have any questions or would you like to see more details?


Related Questions:

  1. How do you derive the amplitude of a trigonometric function from points?
  2. What steps are involved in determining the period of a cosine function from given points?
  3. How do you find the vertical shift in a trigonometric function?
  4. How does phase shift affect the graph of a cosine function?
  5. How can the cosine function be used to model real-world periodic phenomena?
  6. What is the significance of the period TT in a trigonometric function?
  7. How does changing the amplitude affect the appearance of the cosine graph?
  8. What role does the vertical shift dd play in adjusting the baseline of the graph?

Tip: When adjusting trigonometric functions to fit data points, carefully observe the symmetry and key points, like maximums and minimums, to deduce transformations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometry
Cosine Function

Formulas

Cosine function: y = a cos(bx + c) + d
Period of cosine function: T = 2π / b

Theorems

-

Suitable Grade Level

Advanced High School