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To solve \( \left( -1 + i \sqrt{3} \right)^{10} \) using De Moivre's Theorem, we first need to express the complex number in polar form.

### Step 1: Convert to Polar Form
A complex number \( z = x + iy \) can be written in polar form as:

\[
z = r \left( \cos \theta + i \sin \theta \right)
\]

Where:
- \( r = \sqrt{x^2 + y^2} \) is the modulus of the complex number,
- \( \theta = \arg(z) = \tan^{-1} \left( \frac{y}{x} \right) \) is the argument of the complex number.

For \( z = -1 + i\sqrt{3} \):
- \( x = -1 \)
- \( y = \sqrt{3} \)

1. **Find the modulus \( r \):**
   \[
   r = \sqrt{(-1)^2 + (\sqrt{3})^2} = \sqrt{1 + 3} = \sqrt{4} = 2
   \]

2. **Find the argument \( \theta \):**
   \[
   \theta = \tan^{-1} \left( \frac{\sqrt{3}}{-1} \right) = \tan^{-1}(-\sqrt{3})
   \]

Since \( \tan^{-1}(-\sqrt{3}) \) corresponds to an angle of \( 120^\circ \) or \( \frac{2\pi}{3} \) radians in the second quadrant, we have:
\[
\theta = \frac{2\pi}{3}
\]

Thus, the polar form of \( -1 + i\sqrt{3} \) is:
\[
z = 2 \left( \cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3} \right)
\]

### Step 2: Apply De Moivre’s Theorem
De Moivre's Theorem states:
\[
\left( r \left( \cos \theta + i \sin \theta \right) \right)^n = r^n \left( \cos(n\theta) + i \sin(n\theta) \right)
\]

For \( n = 10 \), we calculate:

1. **Modulus raised to the power 10:**
   \[
   r^{10} = 2^{10} = 1024
   \]

2. **Argument multiplied by 10:**
   \[
   n\theta = 10 \times \frac{2\pi}{3} = \frac{20\pi}{3}
   \]

To simplify \( \frac{20\pi}{3} \), subtract \( 6\pi \) (equivalent to two full circles) to get:
\[
\frac{20\pi}{3} - 6\pi = \frac{2\pi}{3}
\]

Thus, the angle simplifies back to \( \frac{2\pi}{3} \).

### Step 3: Final Expression
Using these values, we get:
\[
\left( -1 + i\sqrt{3} \right)^{10} = 1024 \left( \cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3} \right)
\]

From trigonometry, we know:
- \( \cos \frac{2\pi}{3} = -\frac{1}{2} \)
- \( \sin \frac{2\pi}{3} = \frac{\sqrt{3}}{2} \)

Therefore:
\[
\left( -1 + i\sqrt{3} \right)^{10} = 1024 \left( -\frac{1}{2} + i \frac{\sqrt{3}}{2} \right)
\]

Finally:
\[
\left( -1 + i\sqrt{3} \right)^{10} = -512 + 512i\sqrt{3}
\]

### Final Answer:
\[
\boxed{-512 + 512i\sqrt{3}}
\]

Would you like further clarifications or more details?

Here are five related questions to expand your understanding:
1. How can we generalize De Moivre's Theorem for any complex number?
2. What is the geometric significance of multiplying a complex number by itself multiple times?
3. How would you convert from polar to rectangular form in complex numbers?
4. How does De Moivre's Theorem relate to Euler's formula?
5. What happens to the modulus and argument when raising a complex number to a power?

**Tip:** Always ensure the argument \( \theta \) lies within the correct quadrant when working with complex numbers in polar form.

Find the value of (-1 + i√3)^{10} using De Moivre's Theorem.

Learn how to apply De Moivre's Theorem to solve the complex expression (-1 + i√3)^{10}. This step-by-step guide will show you how to convert the complex number into polar form and raise it to the power of 10. Understand key concepts such as modulus, argument, and polar form of complex numbers.

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