Math Problem Statement

Find the value of x. Given \( \angle BGD = 90^\circ \), \( \angle BGC = 53^\circ \), and \( \angle CGD = (3x + 4)^\circ \).

Solution

To solve the given problem, let’s analyze the situation step by step:

Problem Breakdown:

  1. Given:

    • A right angle at point GG, meaning BGD=90\angle BGD = 90^\circ.
    • BGC=53\angle BGC = 53^\circ.
    • CGD=(3x+4)\angle CGD = (3x + 4)^\circ.
  2. Angles in a triangle: The sum of the angles around GG (point where the angles meet) is 9090^\circ. This is because BGD\angle BGD is a right angle.

    Therefore: BGC+CGD=90\angle BGC + \angle CGD = 90^\circ

  3. Substitute the given values: 53+(3x+4)=9053^\circ + (3x + 4)^\circ = 90^\circ

  4. Simplify the equation: Combine like terms: 53+3x+4=9053 + 3x + 4 = 90 3x+57=903x + 57 = 90

  5. Solve for xx: Subtract 5757 from both sides: 3x=333x = 33 Divide by 33: x=11x = 11

Final Answer:

x=11x = 11

Let me know if you’d like a detailed explanation for each step or additional clarifications!

Expanding Understanding:

  1. How do you identify the relationship between angles at a point?
  2. What other properties of triangles can help in solving such problems?
  3. Can you calculate CGD\angle CGD using the found xx?
  4. What are other common problems involving angles around a point?
  5. How do supplementary angles differ from complementary angles?

Tip: Always verify your solution by substituting the value of xx back into the equation to ensure the angles sum correctly!

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Math Problem Analysis

Mathematical Concepts

Angle Sum
Linear Equations

Formulas

Sum of angles around a point: \( \angle BGC + \angle CGD = 90^\circ \)

Theorems

Complementary angles theorem

Suitable Grade Level

Grades 6-8