Math Problem Statement

Test for consistency and solve if possible = x + y + z = 2, 2x + 2y - z = 1, 3x + 4y + z = 9.

Solution

We are given a system of three linear equations:

1.x+y+z=21. \, x + y + z = 2 2.2x+2yz=12. \, 2x + 2y - z = 1 3.3x+4y+z=93. \, 3x + 4y + z = 9

Step 1: Check for Consistency

We need to check if these equations are consistent and have a solution. One way to do this is by solving the system using the method of elimination or substitution.

Step 2: Solve the system using elimination

Subtract the first equation from the second to eliminate zz:

(2x+2yz)(x+y+z)=12(2x + 2y - z) - (x + y + z) = 1 - 2 x+y2z=1x + y - 2z = -1

We get: 4.x+y2z=14. \, x + y - 2z = -1

Subtract the first equation from the third to eliminate zz:

(3x+4y+z)(x+y+z)=92(3x + 4y + z) - (x + y + z) = 9 - 2 2x+3y=72x + 3y = 7

We get: 5.2x+3y=75. \, 2x + 3y = 7

Step 3: Solve the reduced system

We now have two equations: x+y2z=1(Equation 4)x + y - 2z = -1 \quad \text{(Equation 4)} 2x+3y=7(Equation 5)2x + 3y = 7 \quad \text{(Equation 5)}

Solve Equation 5 for xx:

2x+3y=7x=73y22x + 3y = 7 \quad \Rightarrow \quad x = \frac{7 - 3y}{2}

Substitute xx in Equation 4:

(73y2)+y2z=1\left(\frac{7 - 3y}{2}\right) + y - 2z = -1 Multiply the whole equation by 2 to eliminate the fraction: (73y)+2y4z=2(7 - 3y) + 2y - 4z = -2 Simplify: 7y4z=27 - y - 4z = -2 y+4z=9(Equation 6)y + 4z = 9 \quad \text{(Equation 6)}

Step 4: Solve Equation 6

Solve for yy in terms of zz: y=94zy = 9 - 4z

Step 5: Substitute yy into xx:

Substitute y=94zy = 9 - 4z into the expression for xx: x=73(94z)2x = \frac{7 - 3(9 - 4z)}{2} Simplify: x=727+12z2=20+12z2=10+6zx = \frac{7 - 27 + 12z}{2} = \frac{-20 + 12z}{2} = -10 + 6z

Step 6: Substitute xx and yy into the first equation:

Now substitute x=10+6zx = -10 + 6z and y=94zy = 9 - 4z into the first equation x+y+z=2x + y + z = 2: (10+6z)+(94z)+z=2(-10 + 6z) + (9 - 4z) + z = 2 Simplify: 1+3z=2-1 + 3z = 2 3z=3z=13z = 3 \quad \Rightarrow \quad z = 1

Step 7: Solve for xx and yy:

Substitute z=1z = 1 back into the expressions for xx and yy: x=10+6(1)=4x = -10 + 6(1) = -4 y=94(1)=5y = 9 - 4(1) = 5

Final Solution:

The solution to the system is: x=4,y=5,z=1x = -4, \quad y = 5, \quad z = 1

The system is consistent and the solution is: (x,y,z)=(4,5,1)(x, y, z) = (-4, 5, 1)

Would you like further clarification or details on any steps?


Related Questions:

  1. How do you determine if a system of linear equations is inconsistent?
  2. What is the geometric interpretation of the solution to a system of three linear equations?
  3. Can matrix methods (like Gaussian elimination) be used to solve this system more efficiently?
  4. What is the general form of a system of linear equations in three variables?
  5. How can substitution be used effectively in solving more complex systems?

Tip: Always check your solution by substituting the values back into the original equations to verify correctness!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Systems of Equations
Substitution Method
Elimination Method

Formulas

Substitution method: x = (expression)
Elimination of variables by subtraction

Theorems

Consistency of systems of linear equations
Solution to a system of equations in three variables

Suitable Grade Level

Grades 10-12