Math Problem Statement

Solve the questions

Solution

Let's go through the questions one by one.

Question Four: Find the derivatives of the following

  1. y=sin2(4x+π3)y = \sin^2(4x + \frac{\pi}{3})
    To find the derivative dydx\frac{dy}{dx}, we can use the chain rule.

    y=sin2(u)whereu=4x+π3y = \sin^2(u) \quad \text{where} \quad u = 4x + \frac{\pi}{3} First, find the derivative of sin2(u)\sin^2(u) with respect to uu: dydu=2sin(u)cos(u)=sin(2u)\frac{dy}{du} = 2\sin(u)\cos(u) = \sin(2u) Next, differentiate u=4x+π3u = 4x + \frac{\pi}{3} with respect to xx: dudx=4\frac{du}{dx} = 4 Combine these using the chain rule: dydx=dydududx=sin(2u)4=4sin(2(4x+π3))\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} = \sin(2u) \cdot 4 = 4\sin(2(4x + \frac{\pi}{3})) Simplifying further: dydx=4sin(8x+2π3)\frac{dy}{dx} = 4\sin(8x + \frac{2\pi}{3})

  2. y=(2x3+4x2+5)10y = (2x^3 + 4x^2 + 5)^{10}
    Again, using the chain rule: y=(v)10wherev=2x3+4x2+5y = (v)^{10} \quad \text{where} \quad v = 2x^3 + 4x^2 + 5 Differentiate: dydv=10v9\frac{dy}{dv} = 10v^9 Then: dvdx=6x2+8x\frac{dv}{dx} = 6x^2 + 8x Combine these: dydx=10(2x3+4x2+5)9(6x2+8x)\frac{dy}{dx} = 10(2x^3 + 4x^2 + 5)^9 \cdot (6x^2 + 8x)

  3. y=x2e3x+5y = x^2 e^{3x} + 5
    Use the product rule for x2e3xx^2 e^{3x} and differentiate 5 (which is constant): dydx=2xe3x+x23e3x=2xe3x+3x2e3x\frac{dy}{dx} = 2x e^{3x} + x^2 \cdot 3e^{3x} = 2xe^{3x} + 3x^2 e^{3x} The derivative is: dydx=e3x(2x+3x2)\frac{dy}{dx} = e^{3x}(2x + 3x^2)

Question Five

  1. Calculate dydx\frac{dy}{dx} for the following functions:

    a) y=5x22x35+3y = 5x^2 - \frac{2x^3}{5} + 3
    Differentiate each term: dydx=10x6x25\frac{dy}{dx} = 10x - \frac{6x^2}{5}

    b) y=12x34x2+10y = 12x^3 - 4x^2 + 10
    Differentiate each term: dydx=36x28x\frac{dy}{dx} = 36x^2 - 8x

  2. Integrate the following functions with respect to xx:

    a) y=3x23x4+8y = 3x^2 - 3x^4 + 8
    Integrate term by term: ydx=x33x55+8x+C\int y \, dx = x^3 - \frac{3x^5}{5} + 8x + C

    b) y=2x3x2+4x+1y = 2x^3 - x^2 + 4x + 1
    Integrate term by term: ydx=2x44x33+2x2+x+C=x42x33+2x2+x+C\int y \, dx = \frac{2x^4}{4} - \frac{x^3}{3} + 2x^2 + x + C = \frac{x^4}{2} - \frac{x^3}{3} + 2x^2 + x + C

Would you like further details on any specific part or have any questions?


Here are 5 related questions that could expand your understanding:

  1. How do you apply the product rule when differentiating a product of three functions?
  2. What is the significance of the constant CC in indefinite integrals?
  3. How can we use integration to find the area under a curve?
  4. What are some real-world applications of derivatives?
  5. How do higher-order derivatives relate to the original function?

Tip: When solving complex derivatives or integrals, breaking down the problem into smaller parts can make the process easier to manage.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Integration
Chain Rule
Product Rule

Formulas

Derivative rules
Integral rules

Theorems

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Suitable Grade Level

Advanced High School and Above