Math Problem Statement

Using the slope-deflection method, determine the moments at A, B, C and D of the beam shown in Figure 1, then draw the moment diagram for the beam. Assume the support at A and D are fixed and B and C are rollers. EI is constant.

Solution

To solve this problem using the slope-deflection method, we'll go through the following steps:

  1. Identify the spans and fixed supports:

    • Span AB = 5m
    • Span BC = 3m
    • Span CD = 5m
    • Supports at A and D are fixed, while B and C are roller supports.
  2. Calculate fixed-end moments (FEM):

    • Fixed-end moments occur due to the distributed load on span BC.
  3. Write the slope-deflection equations:

    • The slope-deflection equations for each span will consider the rotation at each node and the fixed-end moments.
  4. Apply equilibrium conditions at the roller supports (B and C):

    • This will give us the equations needed to solve for the rotations at B and C.
  5. Calculate moments at A, B, C, and D:

    • Use the slope-deflection equations and the calculated rotations to find the moments.
  6. Draw the moment diagram:

    • Based on the calculated moments, sketch the moment diagram for the beam.

Step 1: Fixed-End Moments (FEM)

For a uniformly distributed load w=20kN/mw = 20 \, \text{kN/m} on span BC (length L=3mL = 3 \, \text{m}):

FEMBC=FEMCB=wL212=20×3212=15kNm\text{FEM}_{BC} = \text{FEM}_{CB} = \frac{wL^2}{12} = \frac{20 \times 3^2}{12} = 15 \, \text{kNm}

Step 2: Slope-Deflection Equations

For spans AB, BC, and CD, the slope-deflection equations are as follows:

MAB=2EILABθA+EILABθBM_{AB} = \frac{2EI}{L_{AB}} \theta_A + \frac{EI}{L_{AB}} \theta_B MBA=2EILABθB+EILABθAM_{BA} = \frac{2EI}{L_{AB}} \theta_B + \frac{EI}{L_{AB}} \theta_A

MBC=2EILBCθB+EILBCθC+FEMBCM_{BC} = \frac{2EI}{L_{BC}} \theta_B + \frac{EI}{L_{BC}} \theta_C + \text{FEM}_{BC} MCB=2EILBCθC+EILBCθB+FEMCBM_{CB} = \frac{2EI}{L_{BC}} \theta_C + \frac{EI}{L_{BC}} \theta_B + \text{FEM}_{CB}

MCD=2EILCDθC+EILCDθDM_{CD} = \frac{2EI}{L_{CD}} \theta_C + \frac{EI}{L_{CD}} \theta_D MDC=2EILCDθD+EILCDθCM_{DC} = \frac{2EI}{L_{CD}} \theta_D + \frac{EI}{L_{CD}} \theta_C

Step 3: Equilibrium Equations

At points B and C (roller supports), the sum of moments must be zero:

MBA+MBC=0M_{BA} + M_{BC} = 0 MCB+MCD=0M_{CB} + M_{CD} = 0

Step 4: Solving the Equations

Substitute the FEM and the given lengths into the slope-deflection equations and solve the system of linear equations for θA\theta_A, θB\theta_B, θC\theta_C, and θD\theta_D.

Step 5: Moment Diagram

After finding the moments at A, B, C, and D, plot these moments to create the moment diagram.

Calculation Execution

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Math Problem Analysis

Mathematical Concepts

Structural Analysis
Slope-Deflection Method
Moment Diagrams

Formulas

Fixed-end moments due to distributed load
Slope-deflection equations

Theorems

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Suitable Grade Level

Advanced Engineering